find the general solution of the first order diff. equation.
e^y + 2xy + (xe^y + x^2)dy/dy = 0
I divided accross by (xe^y + x^2) to get 2ln(y) - ln(x) + dy/dx = 0
Not sure where to take it from here.Help would be greatly appreciated.
find the general solution of the first order diff. equation.
e^y + 2xy + (xe^y + x^2)dy/dy = 0
I divided accross by (xe^y + x^2) to get 2ln(y) - ln(x) + dy/dx = 0
Not sure where to take it from here.Help would be greatly appreciated.