$\displaystyle t^2y'' - 4ty' + 6y$

$\displaystyle y1(t) = t^2

$

given one solution find another solution. I solved this using reduction of order.

I got

$\displaystyle v''t^4 = 0$

where do I proceed from here tho?

I know I have to integrate it or something but im forgetting the steps.