Obtain a power series solution of the equation
xy'' - 2y' + 3y = 0.
I'm not sure where to go with this.
So i just used y= (n=0)SUM(infinity) cnx^(n+r), n got y' and y''.
subbed it into the equation. and simplified to get:
r(r-3)=0 and C[n+1] = 3Cn/(n+r-2)(n+r+1) = 0
r=0 , r=3
is this Frobenius? with difference of positive integer (3)?