The equation I have is 3(dy/dx) + 4y = 4 +6x + 4x^2

I am given that y = 1 when x = 0.

Basically, I can do the initial transform, but afterwards I get completely cnofused. Any help is appreciated.

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- April 28th 2009, 03:01 AMLooNiEHow do I solve this Laplace Transform?
The equation I have is 3(dy/dx) + 4y = 4 +6x + 4x^2

I am given that y = 1 when x = 0.

Basically, I can do the initial transform, but afterwards I get completely cnofused. Any help is appreciated. - April 28th 2009, 03:11 AMmr fantastic
- April 28th 2009, 03:46 AMLooNiEwhat i've done
Ok what I have done is take L.T's, which gives me this:

dont know what the symbol here is but its always Y bar

3(sy - 1) +4y = 4/s + 6/s^2 + 8/s^3

So then I get:

y(3s + 4) = 4/s + 6/s^2 + 8/s^3 + 3

I dont know how to proceed from here. I could obviously divide the rand hand side by (3s+4) but im not completely certain if I need to do anything else first. - April 28th 2009, 03:50 AMmr fantastic
- April 28th 2009, 04:04 AMLooNiE
If I divide on the right hand side, they are all already in partial fracion form. From my teacher, I know that the answer is y = 1 + x^2, but I dont see how I can get the answer from what I have.

- April 28th 2009, 04:30 AMmr fantastic