Need help to solve these two equations: dy = 4y^2 y(-2) = 1/2 dx dy = ye^x y(0) = 1 dx thanks for any help...
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Originally Posted by Saj314 Need help to solve these two equations: dy = 4y^2 y(-2) = 1/2 dx dy = ye^x y(0) = 1 dx thanks for any help... Start with the fact that they are both seperable: $\displaystyle \frac{1}{4} \int \frac{1}{y^2} \, dy = \int dx$. $\displaystyle \int \frac{1}{y} \, dy = \int e^x \, dx$.
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