Need help to solve these two equations:

dy = 4y^2 y(-2) = 1/2

dx

dy = ye^x y(0) = 1

dx

thanks for any help...

Printable View

- April 27th 2009, 05:02 AMSaj314Solving these equations...
Need help to solve these two equations:

dy = 4y^2 y(-2) = 1/2

dx

dy = ye^x y(0) = 1

dx

thanks for any help... - April 27th 2009, 05:06 AMmr fantastic