Need help to solve these two equations:

dy = 4y^2 y(-2) = 1/2

dx

dy = ye^x y(0) = 1

dx

thanks for any help...

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- Apr 27th 2009, 05:02 AMSaj314Solving these equations...
Need help to solve these two equations:

dy = 4y^2 y(-2) = 1/2

dx

dy = ye^x y(0) = 1

dx

thanks for any help... - Apr 27th 2009, 05:06 AMmr fantastic