Thread: Solve the initial value problem

y'' + 4y = 2x; y(0)=1, y'(0)=2

As the title says... thanks for the help

Originally Posted by bearej50

y'' + 4y = 2x; y(0)=1, y'(0)=2

As the title says... thanks for the help

Where are you stuck? Do you know how to find the solution to the homogenous equation y'' + 4y = 0? Do you know how to construct a particular solution?

Originally Posted by bearej50

y'' + 4y = 2x; y(0)=1, y'(0)=2

As the title says... thanks for the help

I'd advise you to check the Differential Equations tutorial

here: http://www.mathhelpforum.com/math-he...-tutorial.html