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Math Help - Homogeneous Equations with Constant Coefficients Part II

  1. #1
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    Homogeneous Equations with Constant Coefficients Part II

    y^(3) + 10y'' + 25y' = 0; y(0) = 3; y'(0) = 4; y''(0) = 5

    Solve the initial value problem
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  2. #2
    MHF Contributor Calculus26's Avatar
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    your characteristic eqn is L^3 +10L^2+25L = 0

    S0 L = 0,-5

    So y = a + be^(-5x) +cxe^(-x)

    now apply ics
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