Hi, is it possible to differentiate; -(1/3)ln|secx|.exp(x).sinx?? do we go about doing this the same way as normal differentiation for example; first differentiate ln|secx| only and so on......?
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Use the product rule. The product is $\displaystyle -\frac{1}{3}\ln |\sec x| \cdot e^x \sin x$. Then, to differentiate [Math]e^x \sin x[/tex] use the product rule again.
Originally Posted by mathsShOck Hi, is it possible to differentiate; -(1/3)ln|secx|.exp(x).sinx?? do we go about doing this the same way as normal differentiation for example; first differentiate ln|secx| only and so on......? yes, it can be differentiated. use the product rule for three functions. $\displaystyle \frac d{dx}[fgh] = f'gh + fg'h + fgh'$ where $\displaystyle f,g, \text{ and }h$ are functions of $\displaystyle x$
Thank you people I got it now.
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