Thread: Solution for intial value problem

y'-y= (2t)(e^(2t))
y(0)=1

Im thinking you have to do something with an integration factor but i have no idea how to use it.

Originally Posted by C-rad

y'-y= (2t)(e^(2t))
y(0)=1

Im thinking you have to do something with an integration factor but i have no idea how to use it.

see the second and third links in my signature

the integrating factor is