1/v dv=-ke^(s/h) ds

Where k is a constant

Im trying to get v as a function of s by sep. of variables and am fairly confused by the algebra. Any help would be appreciated.

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- Apr 2nd 2009, 06:49 PM #1

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- Apr 2nd 2009, 06:52 PM #2

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- Apr 2nd 2009, 06:56 PM #3
The variables are already separated in this case. My solution only works if k and h are constants too.

Integrating : $\displaystyle \int \frac{dv}{v} = \int -ke^{(s/h)} ds$

$\displaystyle ln|v| = -ke^{\frac{s}{h}} \times \frac{h}{s} + C$

Can you solve it from there? I tried going further but could only get to s^s =f(v)

- Apr 2nd 2009, 06:58 PM #4

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