1sr order differential equation

• March 29th 2009, 12:47 AM
zxcv
1sr order differential equation
Hi,

For what value k, is the 2xyy' + y^k = 0 an exaxt differential equation?
• March 29th 2009, 02:52 AM
mr fantastic
Quote:

Originally Posted by zxcv
Hi,

You have $2xy \, dy + y^k \, dx = 0$.
You have $B = 2xy$ and $A = y^k$ and you require $\frac{\partial A}{\partial y} = \frac{\partial B}{\partial x}$.