losve the differnetial equation y' + 2y =2e^x
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Originally Posted by twilightstr is the answer y= 4/3e^4x + 2Ce^x I get Looking at the equation we have So the integrating factor is . Multiplying both sides of the equation by the integrating factor gives The left hand side is a product rule expansion of so we rewrite the equation as .
i messed up on the algebra thanks
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