dy/dx= (2x-y)/(x+y) all subject to y(1) = 1
I am not sure where to take this. I divided everything by x and made the subsequent y/x = V and then worked from there. please can you help
u is just a variable in this case.
$\displaystyle \int{\frac{u'}{u}}$ is a special case of integral and it equals $\displaystyle ln|x| + C$
it is saying that differentiating $\displaystyle 2-2v-v^2$ (the denominator) gives -2-2v which is the numerator. The poster said that u = 2-2v-v^2 and thus u' = -2-2v