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Math Help - eulers method...

  1. #1
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    Exclamation eulers method...

    i'm trying to read and understand from my textbook how to do this method and i am lost. can anyone explain it to me?
    my problem is...
    dy/dx= x-y^2
    y(0)=1
    x is less than or equal to 2 and greater than or equal to 0
    change in x= .25


    use eulers method to approximate the solution of the initial-value problems over the stated interval. present the answer as a table and a graph.

    thank you so much i appreciate it
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  2. #2
    MHF Contributor
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    You could be over-thinking it. We're jsut using the first derivative t approximate the curve over a small displacement.

    Your first point (0,1)
    Your second point (0+0.25, 1+What?)
    We have dy/dx = x - y^2 ==> 0 - 1^2 = -1
    y-displacement is -1*0.25 = -0.25
    Your second point (0+0.25, 1 - 0.25) = (0.25, 0.75)

    Now you have a second point. Calculate the slope there and find the third point.
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