Hi, whats the solution to

-u(x)'' = -pi^2*sin(pi*x)

subject to boundary conditions u(0) = 0, u'(1) = 0

in terms of u(x) = ...

i get u(x) = sin(pi*x) - pi*x , but i think its very wrong

any help much appreiciated thanks !

Results 1 to 2 of 2

- Mar 4th 2009, 05:10 PM #1

- Joined
- Apr 2008
- Posts
- 13

- Mar 4th 2009, 05:49 PM #2

- Joined
- Apr 2005
- Posts
- 18,674
- Thanks
- 2640