Hi, whats the solution to

-u(x)'' = -pi^2*sin(pi*x)

subject to boundary conditions u(0) = 0, u'(1) = 0

in terms of u(x) = ...

i get u(x) = sin(pi*x) - pi*x , but i think its very wrong

any help much appreiciated thanks !

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- Mar 4th 2009, 04:10 PM #1

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- Mar 4th 2009, 04:49 PM #2

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