I am suppose to find the general solution when one solution is given:
9y''' + 11y'' + 4y' -14y = 0
when y= e^(-x)sinx
dont know where to start can someone please help me??
where is a function of x.
Now you will need to take three derivatives of this new function and plug them into the ODE.
I.e here is the first one
Dont forget to use the product rule.
You will end up with an ODE in u and make the substituion that Danny recommended and solve for what u needs to be.
This tells you that the two complex roots of the characteristic equation are -1+i, and -1-i (since the characteristic equation has real coefficients complex roots occur in conjugate pairs and only a linear combinatiation of the solutions corresponding to these roots will give the solution that you have been given).
This should be enough information to allow you to find the third root.