Estimate y(.04), where y(x) is the solution of the initial value problem y'=2xy², y(0)=1 step size=0.1 I got 1.464 but am not sure if I did it correctly.
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starting at x = 0 ... step size = 0.1 ... estimate y(.04) something isn't right. your first step size takes you way past x = .04 starting at x = 0. you sure the step size isn't .01 ?
Estimate y(.4) where y(x) is the solution of the initial value problem y'=2xy^2, y(0)=1 step size=0.1 Sorry for the mistake in the earlier post.
Last edited by mr fantastic; Mar 3rd 2009 at 04:15 PM. Reason: Moved post, added the red
Originally Posted by nystudent2729 Estimate y(.4) where y(x) is the solution of the initial value problem y'=2xy^2, y(0)=1 step size=0.1 I get 1.129 ... what did you do?
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