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Math Help - First order differential equation problem

  1. #1
    Newbie
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    Jul 2008
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    First order differential equation problem

    I should really know the answer to this but am having trouble seeing it

    I have a first order differential
    x\frac{dy}{dx} +\frac{y}{1-x} = (x-1)^2 sinx
    I get the intergrating factor \frac{x}{1-x}
    but when multiplied through to get:
    \frac{x}{1-x}\frac{dy}{dx} + \frac{1}{(1-x)^2} y = (1-x) sinx
    i do not see the what the left side intergral should be any help would be greatly appreciated
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  2. #2
    Math Engineering Student
    Krizalid's Avatar
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    \frac{x}{1-x}\cdot y'+\frac{y}{(1-x)^{2}}=\left( \frac{x}{1-x}\cdot y \right)'.
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