Originally Posted by

**lllll** given the corrections, then would the following be correct:

$\displaystyle (6Bx+2C)+ (Bx^3+Cx^2+Dx+E) =x^3$, then

$\displaystyle (6B+2C)x^3+ (B+C+D+E) =x^3$, where Mr F says: I'm at a loss to understand how you could get this. Where have the x^2 terms and x terms gone on the left hand side? Where has the x^3 term come from?

$\displaystyle {\color{blue}(1)} \ (6B+2C) = 1 \ \mbox{and} \ {\color{blue}(2)} \ (B+C+D+E) = 0$

$\displaystyle B= \frac{1-2C}{6}$ and substituting into the second equation

which ends up giving me $\displaystyle \frac{2}{3} C+D+E = -\frac{1}{6} $

if I let $\displaystyle D$ and $\displaystyle E$ equal to 0 then I get a solution for $\displaystyle C$, but I don't think that I can do that.