Some corrections in red. The bit in blue is important.Solve the following differential equation:
so starting off with the auxiliary equation I have:
where the only available solution is
so I would have:
working on the particular solution I let
substituting for I come up Mr F says: . Therefore .
(this is the part that I get stuck on) Since is a polynomial of third degree I would have:
where Mr F says: . Note the blue bit. This will effect all the calculations that follow.
substituting I get:
so and where I don't think that I'm approaching it correctly since i have 4 unknowns.
any help would be greatly appreciated.