Results 1 to 2 of 2

Math Help - where does he get this term from?

  1. #1
    Newbie
    Joined
    Feb 2009
    Posts
    17

    where does he get this term from?

    I have the differential equation

    dT/ds = C + BT

    which is derived from

    dT = Fds, F = umg + (1/2)CrAv^2, v^2 = 2T/m

    and where

    T = Kinetic energy
    s = distance
    C and B are constants

    I have been shown a solution

    (1/B)*ln(C+BT) = s + D

    I understand that he has done the integral of;

    dT/(C+BT) = ds

    but how does he get the above result?

    integral of 1/x = ln(x)

    Where does the 1/B come from.

    The solution he provoded does not match with my numerical solution.

    Any help would be greatly appreciated
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Jester's Avatar
    Joined
    Dec 2008
    From
    Conway AR
    Posts
    2,347
    Thanks
    30
    Quote Originally Posted by revolution2000 View Post
    I have the differential equation

    dT/ds = C + BT

    which is derived from

    dT = Fds, F = umg + (1/2)CrAv^2, v^2 = 2T/m

    and where

    T = Kinetic energy
    s = distance
    C and B are constants

    I have been shown a solution

    (1/B)*ln(C+BT) = s + D

    I understand that he has done the integral of;

    dT/(C+BT) = ds

    but how does he get the above result?

    integral of 1/x = ln(x)

    Where does the 1/B come from.

    The solution he provoded does not match with my numerical solution.

    Any help would be greatly appreciated
    To integrate \int \frac{dT}{C + BT} if you use the substitution x = C+ BT then dx = B dT and your integral becomes \frac{1}{B} \int \frac{dx}{x}
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Integration term by term and orthogonality
    Posted in the Calculus Forum
    Replies: 2
    Last Post: February 23rd 2011, 03:36 PM
  2. Replies: 1
    Last Post: February 19th 2011, 11:21 AM
  3. Power series, term-by-term integration
    Posted in the Calculus Forum
    Replies: 3
    Last Post: April 8th 2010, 02:14 AM
  4. [SOLVED] Ratio of the second term to the first term
    Posted in the Math Topics Forum
    Replies: 4
    Last Post: September 26th 2008, 06:13 AM
  5. Replies: 7
    Last Post: August 31st 2007, 08:18 PM

Search Tags


/mathhelpforum @mathhelpforum