Originally Posted by

**revolution2000** I have the differential equation

dT/ds = C + BT

which is derived from

dT = Fds, F = umg + (1/2)CrAv^2, v^2 = 2T/m

and where

T = Kinetic energy

s = distance

C and B are constants

I have been shown a solution

(1/B)*ln(C+BT) = s + D

I understand that he has done the integral of;

dT/(C+BT) = ds

but how does he get the above result?

integral of 1/x = ln(x)

Where does the 1/B come from.

The solution he provoded does not match with my numerical solution.

Any help would be greatly appreciated