Originally Posted by
revolution2000 I have the differential equation
dT/ds = C + BT
which is derived from
dT = Fds, F = umg + (1/2)CrAv^2, v^2 = 2T/m
and where
T = Kinetic energy
s = distance
C and B are constants
I have been shown a solution
(1/B)*ln(C+BT) = s + D
I understand that he has done the integral of;
dT/(C+BT) = ds
but how does he get the above result?
integral of 1/x = ln(x)
Where does the 1/B come from.
The solution he provoded does not match with my numerical solution.
Any help would be greatly appreciated