dy/dx = (2x + 5y + 3)/ (4x +y -3).

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- Feb 26th 2009, 04:56 AMfiksidiff eqn
dy/dx = (2x + 5y + 3)/ (4x +y -3).

- Feb 26th 2009, 05:07 AMKrizalid
Put $\displaystyle (u,v)=(x-1,y+1)$ and the ODE becomes $\displaystyle \frac{dv}{du}=\frac{2u+5v}{4u+v},$ which is homogeneous.