dy/dx = (x*e(to pwr of y) )/ x(to pwr of 2) + 1

given conditions y=0 at x=0.

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- February 25th 2009, 02:33 PMfiksidifferential eq, conditions
dy/dx = (x*e(to pwr of y) )/ x(to pwr of 2) + 1

given conditions y=0 at x=0. - February 25th 2009, 02:37 PMKrizalid

Can you take it from there? - February 25th 2009, 02:39 PMskeeter

separate variables ...

do the integration. - February 25th 2009, 02:44 PMfiksi
- February 25th 2009, 02:45 PMKrizalid
Yes, and don't forget the constant.

- February 25th 2009, 02:59 PMfiksi