dy/dx = (x*e(to pwr of y) )/ x(to pwr of 2) + 1

given conditions y=0 at x=0.

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- Feb 25th 2009, 03:33 PMfiksidifferential eq, conditions
dy/dx = (x*e(to pwr of y) )/ x(to pwr of 2) + 1

given conditions y=0 at x=0. - Feb 25th 2009, 03:37 PMKrizalid

Can you take it from there? - Feb 25th 2009, 03:39 PMskeeter

separate variables ...

do the integration. - Feb 25th 2009, 03:44 PMfiksi
- Feb 25th 2009, 03:45 PMKrizalid
Yes, and don't forget the constant.

- Feb 25th 2009, 03:59 PMfiksi