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Math Help - Applied Maths: Diff Eqns

  1. #1
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    Question Applied Maths: Diff Eqns

    We were given sample qs in a lecture and I have a couple of parts of questions that I really need help with so I can complete the question as a whole on my own. Please help me where possible, thanks

    1. How would you go about solving an equation of the form
    dNB/dt=k1NA-k2NB ... where k1,k2 are different constants. [I have an equation for NA that I solved: NA= No e^(-k1*t) if that helps]. I'm not sure how to separate everything as I tried and got into a huge mess...
    I need the solution to substitute into another equation... which I can do... once I have the solution...

    2. " A vase is shaped so that it's cross-sectional area at a height h from its base is:
    A=f(h), O \< h \< H
    where H is the total height of the vase. The vase is filled to the top with water, which then evaporate at a rate proportional to the surface area so that:
    dV/dt= -k*A

    where V(t) is the volume of water and A(t) is the surface area at time t. Show that the height of water in the vase obeys a simple eqn of the form
    dh/dt=-k , with k as a constant, regardless of what the function f is and hence.... ....."

    I don't know where to start with this q, I think you need to change dV so it is in terms of area and height but not sure how to go about it...

    Thanks again! x x x
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  2. #2
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    Quote Originally Posted by tiger_in_the_mist View Post
    We were given sample qs in a lecture and I have a couple of parts of questions that I really need help with so I can complete the question as a whole on my own. Please help me where possible, thanks

    1. How would you go about solving an equation of the form
    dNB/dt=k1NA-k2NB ... where k1,k2 are different constants. [I have an equation for NA that I solved: NA= No e^(-k1*t) if that helps].

    It more than helps it is necessary- you can't solve a single equation for two unknown values, whether numbers or functions!

    Putting N_A into that equation gives \frac{dN_B}{dt}= kN_0e^{-k_1y}- k_2 N_B

    I'm not sure how to separate everything as I tried and got into a huge mess...
    Yes, because that is not a separable equation. I hope that's not the only method you know to solve first order equations. That is a "linear equation" and there is a standard formula for an integrating factor. Do you know that.

    I need the solution to substitute into another equation... which I can do... once I have the solution...

    2. " A vase is shaped so that it's cross-sectional area at a height h from its base is:
    A=f(h), O \< h \< H
    where H is the total height of the vase. The vase is filled to the top with water, which then evaporate at a rate proportional to the surface area so that:
    dV/dt= -k*A

    where V(t) is the volume of water and A(t) is the surface area at time t. Show that the height of water in the vase obeys a simple eqn of the form
    dh/dt=-k , with k as a constant, regardless of what the function f is and hence.... ....."

    I don't know where to start with this q, I think you need to change dV so it is in terms of area and height but not sure how to go about it...

    Thanks again! x x x
    Follow Math Help Forum on Facebook and Google+

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