Find the general solution to the differential equation. Primes denote derivatives with respect toxthroughout.

(2xsin(y)cos(y))y' = 4x^2 + (sin(y))^2

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- Feb 20th 2009, 07:57 AMbearej50Bernoulli Differential Equation
Find the general solution to the differential equation. Primes denote derivatives with respect to

*x*throughout.

(2*x*sin(*y*)cos(*y*))*y*' = 4*x*^2 + (sin(*y*))^2

- Feb 20th 2009, 08:20 AMKrizalid
Make the substitution so that and the ODE is which is linear.

- Feb 20th 2009, 10:35 AMbearej50
I was able to get this far but I am still having trouble. Should the integrating factor be -(1/

*x*) - Feb 20th 2009, 12:02 PMAir
- Feb 22nd 2009, 10:25 PMmatheagle
Any multiple of an integrating factor suffices.

That's why you don't need the +C when you integrate.