Find the general solution to the differential equation. Primes denote derivatives with respect to x. (3y^2)y' + y^3 = e^-x I beleive this is a Bernoulli Equation but I am still having trouble.
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Originally Posted by bearej50 Find the general solution to the differential equation. Primes denote derivatives with respect to x. (3y^2)y' + y^3 = e^-x I beleive this is a Bernoulli Equation but I am still having trouble. Note that the derivative of is try the substitution So we get the equation This can be solved with an integrating factor. Happy Hunting TES
I got that far as well. I cannot figure out what the integrating factor would be because there is no x value attached to the u
Now integrating both sides you get
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