1. ## [SOLVED] Differential

Compute the general solution of the differential equation y' = $\displaystyle 3^x$ by integration.

2. Originally Posted by ronaldo_07
Compute the general solution of the differential equation y' = $\displaystyle 3^x$ by integration.
Use this: $\displaystyle \frac{d}{dx} a^x = a^x*\ln(a)*dx$

3. Is that a general formulae? do you know anywhere that they have a list of these formulaes?

4. so is the answer $\displaystyle 3^x$$\displaystyle ln(3) 5. after differentiating my answer back i realised that my answer should be \displaystyle 3^x x \displaystyle \frac{1}{ln3} how do i get from \displaystyle 3^xln3 to \displaystyle 3^x x \displaystyle \frac{1}{ln3} 6. Originally Posted by ronaldo_07 so is the answer \displaystyle 3^x$$\displaystyle ln(3)$
$\displaystyle \frac{3^x}{\ln{3}}$. You have to divide by ln3 to compensate for when you take the derivative you will multiply by ln3