Originally Posted by

**ben.mahoney@tesco.net** A parachutist falls under gravity and the drag on the chute is known to have an air resistance which is proportional to the square of the velocity *v* and given by *kv2* per unit mass. According to Newton’s Law of Motion the velocity of the parachutist satisfies the differential equation

dv/dt = g - kv^2

where *g* is a gravitational constant. Find the velocity of the particle at any time *t* subject to the initial condition that *v*=0 at *t*=0. Hence confirm that the velocity of the particle tends to the terminal velocity.

Im finding it tricky to differentiate the dv/g-kv^2 bit