Have NO IDEA how to go about this... What is the solution to the IVP (d/dt)y(t) = 4t + 1 and y(1) = 3. Thanks in advance :-)

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Originally Posted by mr_motivator Have NO IDEA how to go about this... What is the solution to the IVP (d/dt)y(t) = 4t + 1 and y(1) = 3. Thanks in advance :-) Integrate both sides with respect to t: y = 2t^2 + t +C. Now substitute t = 1 and y = 3 and solve for C. Your class notes must contain examples like this to follow ....?

Originally Posted by mr fantastic Integrate both sides with respect to t: y = 2t^2 + t +C. Now substitute t = 1 and y = 3 and solve for C. Your class notes must contain examples like this to follow ....? Can anyone show how this is done?

Originally Posted by mr_motivator Can anyone show how this is done? Have you learned how to integrate? Do you know how to substitute values into an equation? Do you know how to solve an equation for an unknown (like C)? Show what you've tried and where you get stuck.

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