(1/y^2)dy=4xdx
integral of ((1/y^2)dy)= integral of (4xdx)
-(1/y)+C1=2x^2+C2
y= -(1/(2x^2))+C assume C2-C1=C
y+(1/2)x^-2=C
so r=1
k=1/2
n=-2
In this question maple has given me a different set of variables that doesnt work out so nicely.
dy/dx = -5*x*y^4
int(y^-4)dy = int (-5*x) dx
1/3y^-3 - 5/2x^2 = C
So when asked for the form y^r + kx^n = C, i have a 2nd constant before the y, namely 1/3, that is damaging to the answer. How could i have done this euation differently to avoid this error?