Given a population differential equation model
dy/dt = y(y-1)(y-3) and y(0)=yo
Solve the following:
solve the mathematical model with yo= .5 (ii)yo =1.5
This is of variables seperable type so:
$\displaystyle
\int \frac{1}{y(y-1)(y-3)}\ dy =\int \ dt
$
or using partial fractions fractions:
$\displaystyle
\int{{1}\over{3\,y}}-{{1}\over{2\,\left(y-1\right)}}+{{1}\over{6\, \left(y-3\right)}}\ dt=t+C
$
Though that may not be where you want to put the constant.
CB