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(dy/dx) + x/y^3 = -3y/x how do i solve this?

Quote: Originally Posted by crafty (dy/dx) + x/y^3 = -3y/x how do i solve this? Standard form $\displaystyle \frac{dy}{dx} + \frac{3y}{x} = - \frac{x}{y^3}$ Multiply by $\displaystyle y^3$ $\displaystyle y^3 \frac{dy}{dx} + \frac{3y^4}{x} = - x$ and make the substitution $\displaystyle u = y^4$. The equation will become linear!