using the substitution u = y-x solve dy/dx = sin(y-x) after substitution i get sin u but then how do integrate with respect to x????
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First thing to notice is that if , then . Substituting into your equation, then, will give you: . Do you see where to take it from here?
i got to the form int (1/(sin u + 1)) du = int dx but how do integrate the part on the left?
Multiply top and bottom by
Originally Posted by Henderson First thing to notice is that if , then . Substituting into your equation, then, will give you: . Do you see where to take it from here? i tried this but shouldn't the correct form be du/dx = sin (u) - 1 and not plus 1 like you wrote, Henderson??
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