# Math Help - how do is solve this differential eqn???

1. ## how do is solve this differential eqn???

dy/dx =[ (e^y)(sin x)^2 ] / [y (sec x)] sorry about the mess, i'm still learning how to use latex

2. Originally Posted by crafty
dy/dx =[ (e^y)(sin x)^2 ] / [y (sec x)] sorry about the mess, i'm still learning how to use latex

$y e^{-y}\,dy = \sin^2x \cos x \, dx$

so

$\int y e^{-y}\,dy = \int \sin^2x \cos x \, dx + c$

Just need to carry out the integrations.

3. (e^(-y))(-y - 1) = (1/3)(sin x)^3 + C this is what i get but do i have to put this in terms of y and if so how would i do that?