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Math Help - how do is solve this differential eqn???

  1. #1
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    how do is solve this differential eqn???

    dy/dx =[ (e^y)(sin x)^2 ] / [y (sec x)] sorry about the mess, i'm still learning how to use latex
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  2. #2
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    Quote Originally Posted by crafty View Post
    dy/dx =[ (e^y)(sin x)^2 ] / [y (sec x)] sorry about the mess, i'm still learning how to use latex
    Your equation separates

    y e^{-y}\,dy = \sin^2x \cos x \, dx

    so

    \int y e^{-y}\,dy = \int \sin^2x \cos x \, dx + c

    Just need to carry out the integrations.
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  3. #3
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    (e^(-y))(-y - 1) = (1/3)(sin x)^3 + C this is what i get but do i have to put this in terms of y and if so how would i do that?
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