# how do is solve this differential eqn???

• February 3rd 2009, 02:50 PM
crafty
how do is solve this differential eqn???
dy/dx =[ (e^y)(sin x)^2 ] / [y (sec x)] sorry about the mess, i'm still learning how to use latex
• February 3rd 2009, 02:53 PM
Jester
Quote:

Originally Posted by crafty
dy/dx =[ (e^y)(sin x)^2 ] / [y (sec x)] sorry about the mess, i'm still learning how to use latex

$y e^{-y}\,dy = \sin^2x \cos x \, dx$
$\int y e^{-y}\,dy = \int \sin^2x \cos x \, dx + c$