dy/dx =[ (e^y)(sin x)^2 ] / [y (sec x)] sorry about the mess, i'm still learning how to use latex

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- February 3rd 2009, 03:50 PMcraftyhow do is solve this differential eqn???
dy/dx =[ (e^y)(sin x)^2 ] / [y (sec x)] sorry about the mess, i'm still learning how to use latex

- February 3rd 2009, 03:53 PMJester
- February 4th 2009, 02:24 PMcrafty
(e^(-y))(-y - 1) = (1/3)(sin x)^3 + C this is what i get but do i have to put this in terms of y and if so how would i do that?