# Thread: Solving Bernoulli equations

1. ## Solving Bernoulli equations

I am in a class on differential equations and do not understand how to solve Bernoulli equations. Here is the problem I have been working on:

y' = ry - k(y^2) , r>0 , k>0

So far I have divided both sides by y^2, and rearranged the equation so that it looks like this:

(y')/(y^2) = (ry)/(y^2) - k(y^2)/(y^2)

(y')/(y^2) = (ry)/(y^2) - k

y'(y^-2) = r(y^-1) - k

y'(y^-2) - r(y^-1) = -k

Could some please help? I have a test tomorrow and I am completely stuck.

2. Originally Posted by CatalinaLou
I am in a class on differential equations and do not understand how to solve Bernoulli equations. Here is the problem I have been working on:

y' = ry - k(y^2) , r>0 , k>0

So far I have divided both sides by y^2, and rearranged the equation so that it looks like this:

(y')/(y^2) = (ry)/(y^2) - k(y^2)/(y^2)

(y')/(y^2) = (ry)/(y^2) - k

y'(y^-2) = r(y^-1) - k

y'(y^-2) - r(y^-1) = -k

Could some please help? I have a test tomorrow and I am completely stuck.
So
$\displaystyle y' = ry - k y^2$

then

$\displaystyle \frac{y' }{y^2}= \frac{r}{y} - k$

If $\displaystyle u = \frac{1}{y}$ then $\displaystyle u' = - \frac{y'}{y^2}$

and your equation becomes

$\displaystyle - u' = r u - k$

or

$\displaystyle u' - r u = k$ linear!

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