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Solve. y'=x(1+y)

Quote: Originally Posted by saiyanmx89 Solve. y'=x(1+y)[/quote] y'/(1+y)= x 1/(1+y) * dy/dx = x dy/(1+y) = x dx \int 1/(1+y)dy = \int x dx + C LN |1+y| = 1/2 x^2 + C |1+y| = e^{0.5 x^2 + C} Can you go on? Cheers Rapha