Hey all,

Solve: x(dy/dx) = y + 2xe^(-y/x)

let v = y/x

v + x(dv/dx) = v + 2e^(-v) two or three steps later gives:

e^vdv = 2(dx)/x integrate and then take ln gives this

v = ln|2ln|x| + C| this is what i am really wondering about

y/x = ln|2ln|x| + C|

y = xln|2ln|x| +C| this is really weird looking, did i do something wrong? Ive done it like five times.

Thanks,