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Math Help - differential equation

  1. #1
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    Talking differential equation

    Hi guys i have that (dy/dx)=(y/2x)-(xy)^3

    i calculated that the general solution is y=ħsqrt(1/{[(2x^4)/5]+[C/x]})
    i used the substitution z=1/y^2
    could someone tell me if i got the right solution please?
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  2. #2
    MHF Contributor
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    Quote Originally Posted by kizler View Post
    Hi guys i have that (dy/dx)=(y/2x)-(xy)^3

    i calculated that the general solution is y=ħsqrt(1/{[(2x^4)/5]+[C/x]})
    i used the substitution z=1/y^2
    could someone tell me if i got the right solution please?
    It's hard to read your expression but if you got

    y = \pm \frac{1}{\sqrt{\frac{2x^4}{5} + \frac{c}{x}}}

    then yes.
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  3. #3
    Eater of Worlds
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    It is difficult to read what you have, but if it is equivalent to y=\pm\sqrt{\frac{5x}{2x^{5}+5C}}

    where \frac{x}{2x^{5}+5C}\geq 0, then you are Okey-dokey

    EDIT: hey, looks like me and big Dan are in the same arena, so I reckon that is it.
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