Hi guys i have that (dy/dx)=(y/2x)-(xy)^3
i calculated that the general solution is y=ħsqrt(1/{[(2x^4)/5]+[C/x]})
i used the substitution z=1/y^2
could someone tell me if i got the right solution please?
It is difficult to read what you have, but if it is equivalent to $\displaystyle y=\pm\sqrt{\frac{5x}{2x^{5}+5C}}$
where $\displaystyle \frac{x}{2x^{5}+5C}\geq 0$, then you are Okey-dokey
EDIT: hey, looks like me and big Dan are in the same arena, so I reckon that is it.