Hi guys i have that (dy/dx)=(y/2x)-(xy)^3

i calculated that the general solution is y=ħsqrt(1/{[(2x^4)/5]+[C/x]})

i used the substitution z=1/y^2

could someone tell me if i got the right solution please?

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- Jan 31st 2009, 09:57 AMkizlerdifferential equation
Hi guys i have that (dy/dx)=(y/2x)-(xy)^3

i calculated that the general solution is y=ħsqrt(1/{[(2x^4)/5]+[C/x]})

i used the substitution z=1/y^2

could someone tell me if i got the right solution please? - Jan 31st 2009, 10:29 AMJester
- Jan 31st 2009, 10:31 AMgalactus
It is difficult to read what you have, but if it is equivalent to $\displaystyle y=\pm\sqrt{\frac{5x}{2x^{5}+5C}}$

where $\displaystyle \frac{x}{2x^{5}+5C}\geq 0$, then you are Okey-dokey(Nod)

EDIT: hey, looks like me and big Dan are in the same arena, so I reckon that is it.:)