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- January 30th 2009, 06:01 AM #1

- Joined
- Oct 2008
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- 124

## Please Help

**(a)**If*k*is a constant, show that a general (one-parameter) solution of the differential equation

*dx/dt = kx*^2is given by*x(t)*= 1/(*C - kt*), where*C*is an arbitrary constant.

**(b)**Determine by inspection a solution of the initial value problem*x'*=*kx*^2,*x*(0) = 0.