y' + 9/4y = 1 - 1/9t y(0) = y0. Find the value of yo for which the solution touches but does not cross the t-axis. So I solve for Y and get Y= (4/9) - (4/9)(t) + (16/81) - 52/81(e^(-9/4t). What do I do next?
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Originally Posted by lord12 y' + 9/4y = 1 - 1/9t y(0) = y0. Find the value of yo for which the solution touches but does not cross the t-axis. So I solve for Y and get Y= (4/9) - (4/9)(t) + (16/81) - 52/81(e^(-9/4t). What do I do next? First off, how did you get this solution? Second ,there's no $\displaystyle y_0$ in your solution.
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