I'm reading this example in my book and I don't get how the author gets this solution.
X1(n) = 2X1(n-1) ; x-sub-1
X2(n) = 2X2(n-1) ; x-sub-2
The solutions to these DEs, according to the book, are
X1(n) = (2^n) * X1(0)
X2(n) = (3^n) * X2(0)
I can't figure out how he makes this leap.
Thanks in advance.