I was wondering if someone could give me some idea as where to start with the following question?

Find in implicit form the general solution of the differential equation

Any help would be greatly appreciated

Thanks

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- Jan 25th 2009, 09:56 AMbobredDifferential equation in implicit form
I was wondering if someone could give me some idea as where to start with the following question?

Find in implicit form the general solution of the differential equation

Any help would be greatly appreciated

Thanks - Jan 25th 2009, 10:29 AMJester
- Jan 25th 2009, 10:34 AMOpalg
- Jan 25th 2009, 11:51 AMbobred
Thanks to you both, it's clear now.

James - Jan 26th 2009, 04:15 AMbobred
Hi

I take is the same as in which case I find the explicit form and solve for y=1/2 and x=0.

But the next part asks for the explicit form which I have had a go at, when I use y=1/2 and x=0 I get a different answer is this correct?

Thanks - Jan 26th 2009, 10:01 AMOpalg
When you do the integration you should get the implicit form of the solution as const. If the initial condition is that y=1/2 when x=0 then the constant is 0. You can then take the square root of both sides to get the explicit solution as . Finally, check the initial condition again to see that you need the + sign, not the – sign.

- Jan 26th 2009, 12:26 PMbobred
Thanks, I'd been looking at it for ages and going round and round in circles.

- Mar 15th 2009, 01:48 PMConfuzed
- Mar 16th 2009, 06:28 AMbobredReciprocal