How to go about solving this differential equation? I tried substitution and could not get any meaningful form of it.
x + y + 1 + (−x + y − 3)y' = 0
You were told the type of DE it is .... To make it more explicit, your DE can be written as:
.
It should be clear what to do now. A similar problem is here: http://www.mathhelpforum.com/math-he...eneous-de.html