Ok I have the equation:
theta^2(d2R/dtheta2)+3theta(dR/dtheta)-8R=20(theta^-3)
The condition is that R=10 when theta=1
I have worked out the equation as far as the General Solution.
The C.F i got was Ae^2t + Be^-4t
I then got a General Solution of Ae^2t + Be^-4t - 4e^-3t
How do I find the values of A and B ?