The DE can be rearranged to the form
what is a function that when differentiated twice gives the function itself
Spoiler:
you can also solve this by separating variables twice
Hello everyone! (Merry Christmas and happy holidays)
I got to solve
-y'' + y = 0
I'm so lost.
I tried cos(x) and sin(x)
then i tried y = sin(-x) => y' = -cos(-x) => y'' = -sin(-x)
=>
The solution is not that obvious, I guess.
Does anyone knows the solution?
Kind regards,
Rapha
The DE has the general form .
The standard technique is to try a solution of the form .
Read these:
PlanetMath: second order linear differential equation with constant coefficients
Homogeneous 2nd-order differential equations
to get started.