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Math Help - Second Order Differential Equation

  1. #1
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    Second Order Differential Equation

    y''' + y' = 2 + sin(x) y(0)=0 y'(0)=1 y''(0) = -1

    I have my homogeneous solution of:
    y(h) = c1 + c2* cos(t) + c3* sin(t)


    When finding my particular solution, I have:
    y(p) = A + B*cos(t) + C*sin(t)

    When taking the y(p)''' + y(p)', I get Zero.


    I am hoping for any hints in finding the Particular solution so I get
    y = y(h) + y(p) to solve for my initial conditions.

    Thanks!
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  2. #2
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    Solved, Thanks.
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