1. ## Equation

A curve which passes through the point (1,0) satisfies the equation dx/dy = x³

Find its equation

thanks for any help

2. Hello, gracey!

A curve which passes through the point (1,0)
satisfies the equation: . $\frac{dx}{dy} \:=\:x^3$
Find its equation
This is a Differential Equation problem . . .

We have: . $\frac{dy}{dx} \:=\:x^{-3} \quad\Rightarrow\quad dy \:=\:x^{-3}\,dx$

Integrate: . $\int dy \;=\;\int x^{-3}\,dx \quad\Rightarrow\quad y \;=\;-\frac{x^{-2}}{2} + C \;=\;-\frac{1}{2x^2} + C$

Since (1,0) satisfies the equation: . $0 \:=\:-\frac{1}{2\cdot1^2} + C \quad\Rightarrow\quad C \:=\:\frac{1}{2}$

Therefore, the equation is: . $y \;=\;-\frac{1}{2x^2} + \frac{1}{2}$

3. Originally Posted by gracey
A curve which passes through the point (1,0) satisfies the equation dx/dy = x³

Find its equation

thanks for any help
$\frac{dy}{dx} = x^{-3}$.

Integrate to get y as a function of x. Use "curve which passes through the point (1,0)" to evaluate the constant of integration.