I have a diff. equation given as;
What is the general solution
to the assosiated diff. equation?
Any help/pointers would be greatly appriciated!
This is in fact the discrete analogue to a differential equation, called a difference equation.
Begin by searching for solutions to the associated homogeneous equation:
Set and substitute to obtain the quadratic , with solutions
.
The general solution to the homogeneous equation becomes , where the are constants.
Now we seek for a particular solution to the original equation. Since the right hand side is a quadratic polynomial in , we can try where are to be determined by substitution.
After this is done, the general solution to the original equation is .